0=6x^2+2x-20+

Solution for 0=6x^2+2x-20+ equation:

0=6x^2+2x-20+

We move all terms to the left:

0-(6x^2+2x-20+)=0

We add all the numbers together, and all the variables

-(6x^2+2x-20+)=0

We get rid of parentheses

-6x^2-2x+20-=0

We add all the numbers together, and all the variables

-6x^2-2x=0

a = -6; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-6)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-6}=\frac{0}{-12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-6}=\frac{4}{-12}
=-1/3
$